Dwyane Wade has agreed to a one-year contract with the Cleveland Cavaliers, where he will reunite with his good friend, LeBron James, according to an ESPN report.
Wade agreed to a contract buyout with the Chicago Bulls on Sunday, and will sign with the Cavaliers once he clears waivers. The deal is for the veterans' minimum, worth $2.3-M.
Aside from Cleveland, Wade was considering his original team, the Miami Heat, as well as the Oklahoma City Thunder and the San Antonio Spurs as his next destinations following a disappointing year with his hometown Bulls.
ESPN reported that it was Wade's longtime friendship with James, "cemented over four seasons and two NBA titles together with the Heat," that eventually compelled the 12-time All-Star to sign with Cleveland.
During Cleveland's media day on Monday, James said he would "love t have D-Wade" as a part of his team.
"I think he brings another championship DNA, championship pedigree. He brings another playmaker to the team who can get guys involved, and make plays, and also just has a great basketball mind," said James.
"I think it would be great to have him here... I hope that we can bring him here. I would love to have him."
Wade joins a Cleveland team that traded away All-Star point guard Kyrie Irving in a tumultuous off season, but added another All-Star point guard in Isaiah Thomas. However, Thomas will not join the team until January as he is still dealing with a bothersome hip injury.
In the meantime, Wade will get to play with James, Kevin Love, JR Smith, and Tristan Thompson.
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